18x^2+27x+9=0

Solution for 18x^2+27x+9=0 equation:

18x^2+27x+9=0

a = 18; b = 27; c = +9;
Δ = b2-4ac
Δ = 272-4·18·9
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-9}{2*18}=\frac{-36}{36}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+9}{2*18}=\frac{-18}{36}
=-1/2
$